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Updated: 13 Jun 2026, 12:22:16

E=mc^2

 

First Equation of Motion

Given:

  • Initial velocity = u
  • Final velocity = v
  • Acceleration = a
  • Time = t

Formula:

 
v = u + at
 

Second Equation of Motion

Distance travelled in time t:

 
s = ut + (1/2)at^2
 

Third Equation of Motion

Formula:

 
v^2 = u^2 + 2as
 

Derivation of the Third Equation

From the first equation:

 
v = u + at
 

Therefore,

 
t = (v - u)/a
 

Substitute into the second equation:

 
s = u[(v - u)/a] + (1/2)a[(v - u)/a]^2
 

Simplifying:

 
s = (uv - u^2)/a + (v - u)^2/(2a)
 

Multiplying both sides by 2a:

 
2as = 2uv - 2u^2 + (v - u)^2
 

Expanding:

 
2as = 2uv - 2u^2 + v^2 - 2uv + u^2
 
 
2as = v^2 - u^2
 

Therefore,

 
v^2 = u^2 + 2as
 

All Three Equations Together

 
v = u + at

s = ut + (1/2)at^2

v^2 = u^2 + 2as
 

These are commonly called Newton's equations (or equations of uniformly accelerated motion). The powers are written in the form you requested, such as v^2, u^2, and t^2.

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